Q. What is the volume of a right-circular cylinder in cm3 having radius 2cm and height 7cm?
(A) 86 cm3
(B) 88 cm3
(C) 90 cm3
(D) 92 cm3
The answer is: (B) 88 cm3
Solution
Here, r=2 and h=7. Hence, by using formula for finding volume of a right-circular cylinder, we have
(A) 21
(B) 22
(C) 23
(D) 24
The answer is: (D) 24
Solution
(A) 5000
(B) 5050
(C) 5100
(D) 5150
The answer is: (B) 5050
Solution
These are the first 100 natural numbers (n=100). So, by applying formula for the sum of the first n natural numbers, we have
(A) 2450
(B) 2500
(C) 2550
(D) 2600
The answer is: (C) 2550
Solution
This is an arithmetic sequence with common difference of 2. The first element is 2, the last element is 100, and total elements (from 2 to 100) are 50. So, a1 = 2, an = 100, d = 2 and n = 50. So, by using the formula for the sum of n elements of an arithmetic sequence, we have
Q. What is: |2| – |–2| – 22 – (–2)2 = ?
(A) –8
(B) –6
(C) –4
(D) –2
The answer is: (A) –8
Solution
(A) 3-2x
(B) 1-2x
(C) 2x-1
(D) (x+3)/2
The answer is: (D) (x+3)/2
Solution
(A) 3-2x
(B) 1-2x
(C) 2x-1
(D) (x+3)/2
The answer is: (D) (x+3)/2
Solution
(A) 260
(B) 268
(C) 280
(D) 288
The answer is: (D) 288
Solution
This is an arithmetic sequence with common difference of 4. The first element is 2, and total elements are 12. So, a1 = 1, d = 3 and n = 12. So, by using the formula of nth term of an arithmetic sequence, first we will find the 12th term
(A) 0
(B) 1
(C) 2
(D) 3
The answer is: (C) 2
The smallest prime number is 2.
A prime number is a natural number greater than 1 that has exactly two distinct positive divisors: 1 and itself. 2 is a prime number because its only divisors are 1 and 2.